Aclerk was asked to change a $10 bill. she returned nine more dimes than nickels, and twenty one more quarters than dimes. how many coins of each did she return

Let x = number of nickels

x + 9 = dimes               (nine more dimes than nickels

x + 9 + 21 = quarters   (21 more qtrs than dimes

.05(x) + .1(x+9) + .25(x + 9 + 21)  = 10

.4x + 8.4 = 10

.4x = 1.6

x = 4     - nickels

x+ 9 = 13    - dimes

x + 30 = 34   - quarters

Hope this helps

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~