Two ships leave a port at the same time. the first ship sails on a bearing of 40° at 18 knots and the secons at a bearing of 130°at 26 knots. how far apart are they after 1.5 hours

The first ship's trajectory and the second ship's trajectory actually form a right angle, since one leaves at 40° and one leaves at 130°, which are 90° apart. The ships' trajectories are therefore two legs of a right triangle. If we find the hypotenuse of the right triangle after 1.5 hours, we will find the distance between the two ships.

After 1.5 hours, the first ship has gone 1.5(18) = 27 nautical miles. The second ship has gone 1.5(26) = 39 nautical miles. So, plug a = 27 and b = 39 into the Pythagorean Theorem to solve for the hypotenuse, c:

c2 = (27)2 + (39)2

c2 = 729 + 1521

c2 = 2250

c = 47.43 nautical miles apart

i think c. but don't trust it.

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet