Find three consecutive integers whose sum is -33

n, n + 1, n + 2 - three consecutive integers

-33 - the sum

Equation:

n + (n + 1) + (n + 2) = -33

n + n + 1 + n + 2 = -33

3n + 3 = -33      |subtract 3 from both sides

3n = -36    |divide both sides by 3

n = -12

n + 1 = -12 + 1 = -11

n + 2 = -12 + 2 = -10

-12, -11, -10.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

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