Passing through (-6,-1) and parallel to y=-2/3x +1 write a linear equation with the given information

Hello!

To find the line parallel to the line y = -2/3x + 1 and passing through the point (-6, -1), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.

Since we are given the slope, we need to find the y-intercept of the line. We can find the y-intercept by substituting the point (-6, -1) into a new equation with the slope of m = -2/3. Remember that slope-intercept form is y = mx + b.

y = -2/3x + b (substitute the ordered pair)

-1 = -2/3(-6) + b

-1 = 4 + b (subtract 4 from both sides)

-5 = b

Therefore, the equation of the line passing through the point (-6, -1) and parallel to y = -2/3x + 1 is y = -2/3x - 5.

is this part of a question or something