Which of the binomials below is a factor of this trinomial? x^2 + 2x - 48

(x + 8)(x - 6)

to factorise consider the factors of - 48 which sum to + 2

These are + 8 and - 6 thus

x² + 2x - 48 = (x + 8)(x - 6)

Factors are (x-8) ( x+6).

Step-by-step explanation:

Given : x²-2x -48 .

To find : Factors .

Solution : We have given x² -2x -48 .

Factories

x² + 6x -8x -48

Taking x common from first two term and - 8 from last two terms

x ( x +6) -8( x +6)

On grouping

( x -8)( x+6)

Therefore, Factors are (x -8) ( x +6) .

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation