What is the solution set of the equation using quadratic formula x^2 + 2x + 5 = 0

Add  

5

to both sides of the equation.

x

2

+

2

x

=

5

Divide the coefficient of the  

x

value by  

2

, then square the result.

2

2

=

1

;

1

2

=

1

Add the result to both sides.

x

2

+

2

x

+

1

=

5

+

1

=

x

2

+

2

x

+

1

=

6

The left side is now a perfect square trinomial.

x

2

+

2

x

+

1

=

(

x

+

1

)

2

(

x

+

1

)

2

=

6

Take the square root on both sides.

x

+

1

=

±

√

6

Subtract  

1

from both sides.

x

=

√

6

−

1

x

=

−

√

6

−

1

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

5.7622

step-by-step explanation:

the ten thousandths place is the 2. you round it up if, that number in whatever place is 5 or higher.