How do you do 6d + 4 + 5d - 2d = 58 ?

To solve this first combine like terms.

6d+4+5d-2d=58

6d+5d=11d

11d-2d=9d

9d+4=58

Then continue by subtracting 4 from both sides of the equation.

9d+4=58

9d+4-4=58-4

9d=54

Divide both sides by 9 to isolate d.

=

d=6

To check if this answer is true, substitute 6 back into the original equation.

6(6)+4+5(6)-2(6)=58

36+4+30-12=58

40+30-12=58

70-12=58

58=58

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse