Ineed writing an equation of a graph in slope-intercept form & standard form. plz (:

y = - x + 2 abd 2x + 3y = 6

The equation of a line in ' slope- intercept form ' is

y = mx + c → ( m is slope and c is the y- intercept)

The  graph here slopes downwards from left to right thus slope is negative

m = - and c = 2

y = - x + 2 in slope- intercept form

the equation of a line in standard form is Ax + By = C

where A is a positive integer and B, C are integers

multiply all terms in the slope- intercept equation by 3

3y = - 2x + 6 → add 2x to both sides

2x + 3y = 6 in standard form

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a