Me! : ) 1) given: △klm lm=12, m∠k=60°,m∠m=45° find: perimeter of △klm. 2) given: △mno m∠m=45°, m∠o=30° mn=6 find: no, mo.

1). Perimeter = 35.18 units

2). NO = 4.24 units, MO = 11.59 units

Step-by-step explanation:

1). Given : In ΔKLM,

LM = 12, m∠K = 60°, m∠M = 45°

Then we have to find the perimeter of the given triangle.

By applying sine rule in the triangle,

Since ∠K + ∠L + ∠M = 180°

60 + ∠L + 45 = 180

∠L + 105 = 180

∠L = 180 - 105

∠L = 75°

KM =

KM = 13.38 unit

Similarly,

KL =

KL = 9.80 unit

Therefore, Perimeter of the triangle = LM + KL+ KM

= 12 + 9.80 + 13.38

= 35.18 units

2). Given in the ΔMNO,

m∠M = 45°, m∠O = 30° and MN = 6 units

To Find : Measure of NO and MO

m∠M + m∠N + m∠O = 180

45 + m∠N + 30 = 180

m∠N + 75 = 180

m∠N = 180 - 75

m∠N = 105°

Now we apply the sine rule in the triangle.

MO =

MO = 11.59 units

NO =

NO = 4.24 units

b. astronomers

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step-by-step explanation: