Me, what is this (function) answer? , addmaths messing up my brain

g {}^{2} (x) =(  \frac{x - 1}{x} ) {}^{2}  \\ g {}^{2} (x) =  \frac{x {}^{2} - 2x + 1 }{x {}^{2} }

g {}^{3} (x) = ( \frac{x - 1}{x} ) {}^{3}  \\ g {}^{3} (x) =  \frac{x {}^{3} - x {}^{2} - 2x {}^{2}  - 2x  + x - 1 }{x {}^{3} }

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Have a nice da!!

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i hate black

idk

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