Solve the equation . 2= 10+z/-3 two equals ten ( 10 ) plus ( + ) ' z ' divided by ( / ) negative ( - ) three ( 3 ) . 15 –4 –5 –16

Solve for

z

Multiply both sides of the equation by −3.

(10+z)=2 x (−3)

Simplify 2x(−3).

Multiply 2 by −3.

(10+z)=2(−3)

Multiply 2 by −3.

(10+z)=−6

Remove parentheses.

10+z=−6

Move all terms not containing z to the right side of the equation.

Subtract 10 from both sides of the equation.

z=−6−10

Subtract 10 from  −6 .

z=−16

- Prodixy ☕

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

i believe the answer is letter c) 8

step-by-step explanation: