The straight line joining the points a(3,-5) and b(6,k) has a gradient of 4. work out the value of k.

The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.

Gradient is the slope

So the slope of the line joining the points A(3,-5) and B(6,k) is 4

Slope of line joining two points =

A(3,-5) and B(6,k) are (x1,y1)  and (x2,y2)

slope =

slope =

We know slope =4

Cross multiply  and solve for k

k + 5 = 12

k = 7

The value of k = 7

42.4

step-by-step explanation:

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