Write a slope intercept for a line passing through the point (4,-3) that is paralell to the line 4x+5y=7

First, we need to solve the equation 4x+5y=7 to make it slope intercept form and find the slope of the line, because parallel lines have the same slope.

4x+5y=7

Subtract 4x from both sides.

5y=-4x+7

Divide both sides by 5.

y=-4/5x+7/5

The slope of the line is -4/5x. Plug that in to the blank slope intercept form equation, y=mx+b, with m being the slope and b being the y-intercept.

y=-4/5x+b

Now, we need to solve for the y-intercept. We can do this by plugging in the given coordinates (4,-3) into the above equation for x and y respectively:

-3=-4/5(4)+b

-3=-16/5+b

Add -16/5 to both sides.

1/5=b

The y-intercept is 1/5, plug this into the equation:

Your equation is the above equation.

I hope this helps :)

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car