Amotel clerk counts his $1 and $10 bills at the end of the day. he finds that he has a total of 53 bills having a combined monetary value of $ 182. find the number of bills of each denomination that he has. the clerk ones and tens.

A motel clerk counts his $1 and $10 bills at the end of the day. He finds that he has a total of 53 bills having a combined monetary value of $ 182.

let x be the number of $1 bills  

y be the  number of $10 bills

There are total of 53 bills so the equation becomes

 x+y=53 ---> first equation

Bills having a combined monetary value of $ 182

x + 10 y = 182 ----> second equation

Now we solve for x  and y

 x+y=53

y = 53 - x

Now plug in 53 - x in second equation

(subtract 530 on both sides)

-9x= -348

Recheck the numbers given in the question. because we got answer in fraction form.

We know y = 53 - x

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages