The vertices a(–2, –1), b(–3, 2), c(–1, 3), and d(0, 0) form a parallelogram. the vertices a’(–1, –2), b’(2, –3), c’(3, –1), and d’(0, 0) are the image of the parallelogram after a sequence of transformations. which sequence of transformations could produce the image from the pre-image? a reflection over the x-axis and then a reflection over the y-axis a reflection over the y-axis and then a 90 degree clockwise rotation about the origin a 90 degree clockwise rotation about the origin and then a reflection over the y-axis a 90 degree counterclockwise rotation about the origin and then a reflection over the x-axis

In the attachment, the original parallelogram is shown in red. Its image is shown in blue. The purple parallelogram is the original reflected across the y-axis. You can see that it becomes the blue parallelogram if rotated 90° clockwise around the origin.

The appropriate choice is ...

... a reflection over the y-axis and then a 90 degree clockwise rotation about the origin

table 1

step-by-step explanation:

1-16

2-32

4-64

8-128

all multiples of 16

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)