The equation x^2-9=0 has how many real solutions

So remember that the degree of the polynomial will indicate how many solutions there are, real or complex. Since the degree of the polynomial is 2, this means that there is a maximum of 2 real solutions in this equation.

Next, we are going to apply the difference of squares rule to this polynomial, which is . In this case:

Now, we are going to apply the Zero Product Property, which states that if a × b = 0, this means that either a or b = 0 or a and b = 0. In this case, a = x + 3 and b = x - 3. Solve each as such:

In short, there are 2 real solutions: x = 3 and x = -3.

answer: y=0 if that is what u r looking for