10 , i am s lost. given that f(x)=x+7 and g(x)=sqrt(x-4), find (f-g)(1), if it exists. i got the answer 8-sqrt(-3) does this exist? i remember hearing about 3i, but do imaginary numbers exist! ? reee

x + 7 - √(x - 4)

Replace x with 1.

1 + 7 - √(1 - 4)

1 + 7 - √(-3)

1 + 7 - i√3

8 - i√3 is your final answer.

You were very close.

When you have a negative number under a radical, you can multiply it by i to make it not a negative.

The simplified form of √-3 is i√3.

Your answer is 8 - i√3.

(Yes imaginary numbers exist :3)

the answer is 31.27mph

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.