Determine the truth value of the statement when p is t, q is f, and r is f ( p ↔ q ) → ( ∼ p ∨ r )

Given P is T, q is F and r is F.

Let us find p ↔ q first.

↔ is called bi-conditional operator and is true when p and q both are matched.

Since here p is T and q is F, p↔q is F. ( Since p and q are not matching)

~p v r = ~T v F = F v F = F

Hence (p↔q)→(~pvr) = F → F = T     (Since conditional operator → is false if and if first proposition is T and second proposition is F, for all other values it is T)

a is the right answer