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Mathematics, 21.06.2019 14:30
Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.
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Mathematics, 22.06.2019 03:30
Millie decided to purchase a $17,000 msrp vehicle at a 4% interest rate for 6 years. the dealership offered her a $2700 cash-back incentive, which she accepted. if she takes all these factors into consideration, what monthly payment amount can she expect? a.$223.73b.$243.25c.$274.61d.$235.51
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