The point slope form of the equation of the line that passes through (-4 -3) and (12, 1) is y - 1 = 1/4 (x - 12). what is the standard form of the equation for this line?

Standard Form is ...

ax + by = c

where a ≥ 0, b > 0 (if a=0), and {a, b, c} are mutually prime integers (unless irrational numbers are involved).

You can get there from where you're starting in a couple of steps. Multiply by the least common denominator of any fractions. (Here, you multiply by 4.) Then put the variable terms on the opposite side from the constant term. Make sure the leading coefficient is positive.

... 4y -4 = x -12

... x -4y = 8 . . . . add 12-4y

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

a

step-by-step explanation: