Point c ∈ ab, ab = 30m. point c is 1.5 times farther from point a than from point b. find ac and cb.

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC

Point C is 1.5 times farther from point A than from point B

so, we get

now, we can plug values

now, we can solve for x

so, we get

now, we can find CB

so, we get

...............Answer

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x