For y = 3x - 2x^2 + 5x^3, show how to find the value for y when x = 3. show your work.

When x = 3 just substitute in equation and solve

y = 3(3)- 2x^2 + 5x^3

Y= 9-2(3)^2+5(3)^3

Y = 9-18+135

Y= 126

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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