How do i solve for x here? use the properties of logarithms to find a value for x. assume a, b, and m are constants. [tex]ln(a*b^{x}) = m[/tex] the answer in the back of the textbook is [tex]x=rac{m-ln(a)}{ln(b)}[/tex] but i am unsure how to get to that solution. do i start with ln(a) + ln(b)^x?

Yes, you're right! The first step is rewriting the equation asSubtract from both sides:Use the prop...

Mathematics, 07.07.2019 12:00 realoneree

How do i solve for x here? use the properties of logarithms to find a value for x. assume a, b, and m are constants. $ln(a*b^{x}) = m$ the answer in the back of the textbook is $x=\frac{m-ln(a)}{ln(b)}$ but i am unsure how to get to that solution. do i start with ln(a) + ln(b)^x?

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