Aline has slope of -3 and passes through the point (5,-1). what is the equation of the line?

Y=mx+b

So you have slope and a point substitute to find b.

Y= mx+b

-1= -3(5)+b

-1=-15+b

-1+15=b

14=b

Now put equation together using slope and b to get your equation

Y= -3x+14