If y varies inversely as the square of x, and y=7/4 when x=1, find y when x=3

y varies inversely as the square of x. So we can write the relation between x and y as:

where k is a constant of proportionality. It is given that y = 7/4 when x = 1.

Using these values, we can write:

So, now the equation in terms of x and y can be written as:

We are to find y when x = 3. So we can write:

Thus, for x= 3 value of y will be 7/36

Hope this helps!!!

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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