X^2-4y^2=0 a.(x+4y)(x-y) b. (x-4y)(x+y) c. (x+2y)(x-2y) d. (x-2y)(x-2y)

-4 = 0

Solution

Here we have to find the factors.

Here we can write 4y^2 as (2y)^2

Now we have to use the formula, a^2 - b^2 = (a + b)(a - b)

Here a = x and b = 2y

Therefore, we get

(x + 2y)(x -2y)

Hence, the answer isC. (x + 2y)(x -2y)

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers