What is the factored form of the expression over the complex numbers? 121x2+36y2 (11x+6y)(11x−6y) (11x+6iy)(11x−6iy) (11x−6iy)(11x−6iy) (11x+6iy)(11x+6iy)

 121x² + 36y²

= 121x² - (-36y²)     Notice that the first and last term are perfect squares.

= (11x - 6iy)(11x + 6iy)     So, you can factor using the difference of squares.

B

(11x + 6iy)(11x - 6iy)

using the difference of squares identity

a² - b² = (a - b)(a +b)

a² + b² = (a - bi )(a + bi)

121x² = ( 11x)² ⇒ a = 11x and 36y² = (6y)² ⇒ b = 6y

121x² + 36y² = (11x - 6iy)(11x + 6iy)

c

step-by-step explanation:

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.