The length of the sides forming a right angle of a right-angled triangle is 5 x cm and 3 x - 1 cm. area of the triangle is 60 cm square. find the hypotenuse

hypotenuse (h) = 17 cm

using area of a triangle formula to solve for x

A = bh ( b is the base and h the height )

× 5x(3x - 1 ) =60 ( multiply through by 2 )

5x(3x - 1)=120

15x² - 5x - 120 = 0 ← in standard form ( divide all terms by 5 )

3x² - x - 24 = 0

consider the factors of the product 3 × - 24 = - 72 which sum to - 1

The factors are - 9 and + 8 ( split the middle term using these factors )

3x² - 9x + 8x - 24 = 0 ( factor by grouping )

3x(x - 3) + 8(x - 3) = 0 ( take out common factor (x - 3) )

(x - 3 )(3x + 8) = 0 ( equate each factor to zero and solve for x )

x - 3 = 0 ⇒ x = 3

3x + 8 = 0 ⇒ x = -

x > 0 ⇒ x = 3

the sides are 5x = 15 and 3x - 1 = 8

h = √(15² + 8² ) = √(225 + 64 ) = 17 ← ( hypotenuse )

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

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step-by-step explanation:

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