This is a trigonometry question. a conveyor is used to lift to a shredder. the most efficient operating angle of elevation for the conveyor is 36.2 degrees. the paper is to be elevated 17.0 m. what length of conveyor is needed?

You can use the sin function to solve this.

Think of a triangle with the conveyor being the longest side (hypotenuse). The height (the vertical side) is H=17m. The angle of elevation is a=36.2. We are looking for length of the hypotenuse, L.

The sin is the ratio of height to hypotenuse: sin(36.2) = H/L = 17/L

Now solve for L:

L = 17/sin(36.2) = 17m/0.59 = 28.78m

The conveyor needs to be approx. 28.8m long to get close to the max. efficient angle.

step-by-step explanation:

|ab| = 1.4 = 4

h = 1.4 = 4

a(abc) area = 4.4 = 16/2 = 8

area of abc = 8 cm^2

good luck ! ; )