Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the largest number

Let consecutive odd numbers be  

x , x+2 , x+4

Smallest number =x

Middle number =x+2

Largest number =x+4

According to condition (x) +(x+2) -27 = 3(x+4)

                                      x+x+2-27= 3(x+4)

                                      2x-25= 3x+12

Subtracting 2x and 12 both sides

                                   2x-25-2x-12=3x+12-2x-12

                                     -37= x   this is smallest odd number.

Other two odd numbers are (x+2)= (-37+2)=(-35)

                             &                (x+4)=(-37+4)=(-33)

so three consecutive odd numbers are -37 ,-35 , -33

your answer is 40

step-by-step explanation: