Given sample set a= {1,2,3,4,5} how many items are in the complement of set b if set b= all numbers greater than 2? (30 pts)

Alright, so first we need to establish two things.

First, the compliment of a set is like the extreme opposite; everything that is not in set B will be in the complement.

Second, we need to find out what B is.

Okay, so B is everything that is greater than 2, that's given. That includes 3, 4, and 5. B = {3, 4, 5}. There are three items in this set.

The numbers that aren't included are 1 and 2. The complement of B, let's call this C I guess, is C = {1, 2}. There are 2 items in this set.

The answer, I believe, is two. Hope this helps!

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629