What is the solution to the system of equations represented by the two equations? y=2/3x y=-2/3x+4 l l v v ( ? , ? )

These are simultaneous equations of straight lines.

y = 2/3x ... (i)

y = -2/3 + 4 ... (ii)

(i) + (ii) gives 2y = 4 , y = 2

So 2 = 2/3x , x = (3 × 2) ÷ 2 = 3

x = 3

The two lines with equations y = 2/3x and y = -2/3x + 4 meet at

(x,y) = (3,2)

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3