Geometry ! what is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?

A perpendicular line has the negative reciprocal slope of the given line.

The slope of the given line is x/2, which can be written as 1/2x

The negative reciprocal of 1/2 would be -2

The equation for a line is written as y = mx +b, where m is the slope and b is the y-intercept.

We already have the slope ( -2)

So we can solve for b by replacing y x and m with the slope and the point given:

8 = -2(1) +b

8 = -2 + b

b = 10

The equation would be y = -2x + 10

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step-by-step explanation:

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