Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the largest number?

10,12,14

Step-by-step explanation:

Two consecutive integers will have difference of 2.

Let 3 consecutive even integers be a-2, a, a+2

Smallest number = a-2 and middle number = a

Sum of the smallest number and twice the middle number

= a-2+2a =3a-2

20 more than the largest number = 20+a+2 =a+22

i.e. 3a-2 = a+22

2a = 24

Or a =12

Hence three integers even consecutive are 12-2, 12, 12+2

=10,12,14

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

answer: what is the conflict?

step-by-step explanation:

*what has happened to new york city?

*what is in the time capsule?

* what did the kidz see that gave them hope?

*what will they do with what they find?

* how will they save the city?

* what challenges will they face along the way?

*what big choice will they make at the climax of the story?

* what lesson do they learn at the end of the story?