The equation y-5=6(x+1) is written in point-slope form. what is the equation written in slope-intercept form? y = 6x + 11y = 6x – 1 y = 6x – 4y = 6x + 6

The slope-intercept form: y = mx + b

We have in point-intercept form: y - 5 = 6(x + 1)

Transform:

y - 5 = 6(x + 1)     |use distributive property

y - 5 = (6)(x) + (6)(1)

y - 5 = 6x + 6     |add 5 to both sides

y = 6x + 11

answer: huh

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.