If f(x) = 2x^2 + 1 and g(x) = x^2 - 7, find (f - g)(x).

Step-by-step explanation:

If f(x)=3x^2-2x+4, then

f(x + h)

= 3(x + h)^2 -2(x + h) + 4

=3(x^2 + 2hx + h^2) - 2(x + h) +4

= 3x^2 + 6hx + 3h^2 - 2x -2h + 4

So

f(x+h)-f(x)

= 3x^2 + 6hx + 3h^2 - 2x -2h + 4 - (3x^2 - 2x + 4)

= 3x^2 + 6hx + 3h^2 - 2x -2h + 4 - 3x^2 + 2x - 4

= 6hx + 3h^2 - 2h

i think this could be a possible answer (1 / 84) -1

good luck! : d

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