Find an equation parallel to x=4 that goes through (-6, 1)

The equation to a line parallel to x = 4 including that point is x = -6.

Step-by-step explanation:

In order to find the value of this equation, we first need to see the value of the slope. Since the original equation is x = 4, we know that the slope is undefined (a vertical line). Therefore, the parallel line must also be vertical.

A vertical line going through (-6, 1) would have to be x = -6, otherwise it would not hit the point.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: