How do i find the zeros of x^4-10x^3-66x^2-94x-39

x = -1, -3, 7 + √62, 7 - √62

Step-by-step explanation:

q                                    p

x⁴ - 10x³ - 66x² - 94x - 39

= +/-

possible rational factors: 1, -1, 3, -3, 13, -13, 39, -39

Use synthetic division or long division to see which factor will leave a remainder of 0.

try x + 1 = 0  ⇒   x = -1

-1   |  1     -10     -66     -94     -39

    |  ↓     -1        11        55      39

       1     -11      -55     -39       0

(x + 1)(x³ - 11x² - 55x - 39)        

next, try x + 3 = 0  ⇒   x = -3   for the new polynomial

-3   |  1     -11     -55     -39

     |  ↓     -3       42     39

        1     -14      -13       0  

(x + 1)(x + 3)(x² - 14x - 13)

Lastly: find the zeros by setting each factor equal to zero and solve.

x + 1 = 0  ⇒  x = -1

x + 3 = 0   ⇒ x = -3

x² - 14x - 13 = 0

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.

nlgqer

step-by-step