Atrain leaves roseville heading east at 6: 00 am at 40 miles per hour. another eastbound train leaves on a parallel track at 7: 00 am at 50 miles per hour. what times will it be when the two trains are at the same distance away from roseville?

At 11:00 am the both trains will be at same distance away from Roseville

Step-by-step explanation:

The first train was 40 miles away from Roseville at 7:00 am

After some time t the both trains will be at the same distance away from Roseville.

We will make equation for that situation

d- distance      v1= 40mph and v2= 50mph -  velocity

d =  v1*t + 40 = v2*t  => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)

t = 40/(50-40) = 40/10= 4h      t = 4h

7:00 am * 4h = 11:00 am

Good luck!!!

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate