What are the x and y intercepts of the line 3x-4y=12

x-intercept = 4, y-intercept = - 3

to find the intercepts, that is where the graph crosses the axes

let x = 0, in the equation for y- intercept

let y = 0, in the equation for x- intercept

x = 0 : - 4y = 12 ⇒ y = - 3 ⇒ (0, - 3) ← y - intercept

y = 0 : 3x = 12 ⇒ x = 4 ⇒ (4, 0 ) ← x- intercept

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.