graph the equation

Step-by-step explanation:

This equation represents a parabola that opens up.  

Comparing y = 5(x-1)^2 - 5 to y = a(x-h)^2 + k, we see that h = 1 and k = -5.  Thus, we know that the vertex is (1, -5).  Plot this point.  

Next, find the y-intercept.  Let x = 0 and find y:  y = 5(0 - 1)^2 - 5 = 0.  Thus, the y-intercept is at (0,0).  Plot this point.  Draw the axis of symmetry; it's the vertical line that passes thru the vertex:  x = 1.  Note that the y-intercept is 1 unit to the left of x = 1.  Reflect the y-intercept across the axis of symmetry, x = 1, obtaining (0, 2).  Plot this point.  Now you have 3 points and know that the graph is symmetrical about x = 1.  Draw a smooth curve through these three points.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

step-by-step explanation: