Graph the following lines and using the graph determine several values of x for which the graph is positive (negative): y = -0.5x - 2 y is positive when blank x is positive when blank

Step-by-step explanation:

Given equation is,

y=-0.5x-2

when x=-2 , y=-0.5(-2)-2=1-2=-1

when x=0 , y=-0.5(0)-2=0-2=-2

when x=2 , y=-0.5(2)-2=-1-2=-3

So, we get the points (-2,-1) , (0,-2) , (2,-3)

Now, using the points on the graph and adding them, we will get the graph of given line.

Please check image for the graph.

Now for the second part- we have to find values of x , for which y is positive.

That means, y will be above the x-axis.

From the graph we can see that-  when x<-4,

then the graph is above the x-axis.

So, for all values of x, which are less than  -4,

we will get the positive graph.

step-by-step explanation:

kjswgdkxg

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116