Write 6(x – 5)4 + 4(x – 5)2 + 6 = 0 in the form of a quadratic by using substitution. a. 6u2 + 4u + 6 = 0, where u = x – 5 b. 6u2 + 4u + 6 = 0, where u = (x – 5)2 c. 6u4 + 4u + 6 = 0, where u = x – 5 d.6u4 + 4u + 6 = 0, where u = (x – 5)2the answer is  b. 6u2 + 4u + 6 = 0, where u = (x – 5)2 

We are given the equation:

..........(1)

Now we have to write it in quadratic form using substitution.

The general form of quadratic equation is given by:

So let us say

.......(2)

Plugging the value of (x-5)² from equation (2) in (1),

Answer : Option B.

no not all of them.

step-by-step explanation:

some of them have a square base.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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