Aspecies of beetles grows 32% every year. suppose 100 beetles are released into a field. how many beetles will there be in 10 years? a species of beetles grows 32% every year. suppose 100 beetles are released into a field. how many beetles will there be in 20 years? a species of beetles grows 32% every year. suppose 100 beetles are released into a field. about when will there be 100,000 beetles?

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

where A is number of beetles at any year n.

Plug the given values into above formula we get:

now plug n=10 years

Hence answer is approx 1606 beetles will be there after 10 years.

To find answer for 20 years plug n=20 years

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

24.8810001465=n

Hence answer is approx 25 years.

beetles

   beetles

In 24.88 years there will be 100 000 beetles

Step-by-step explanation:

Let's call the beetle population that is in year t. If t starts in year 0, with 100 beetles, and the population grows 32% each year, then the population of beetles that will occur the following year is:

If we write this equation for a year t, then will have the following form:

Now we find

beetles

In 20 years there will be:

 beetles

To know when there will be 100 000 beetles we equal Pt to 100 000 and we clear t.

t = 24.88 years

In 24.88 years there will be 100 000 beetles

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

vbbv

step-by-step explanation: