Find the probability that when a couple has sixsix children, at least one of them is a girlgirl. (assume that boys and girls are equally likely.)

Step-by-step explanation:

"At least one" means:

(1g & 5b) or (2g & 4b) or (3g & 3b) or (4g & 2b) or (5g & 1b) or (6g & 0b)

which is the same as: not(0g & 6b)

not (0g & 6b)

= 1 -

= 1 -

= 1 -

=

step-by-step explanation:

i hate black

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72