Find the exponential regression equation that best fits the data (10,4), (12,20), (12,35), and (16,300) a. y=0.003(2.04)^x b. y=2.04(0.003)^x c. y=11.27(1.00)^x d. y=1.00(11.27)^x

We are exponential equation in form .

We need to find the values of A and B.

We are given points (10,4), (12,20), (12,35), and (16,300).

Let us check equation in option y=0.003(2.04)^x by plugging those given points in that equation.

Plugging  x=10

y=0.003(2.04)^10 = 3.74475.

Plugging x= 12.

y=0.003(2.04)^12 = 15.58416

Plugging x=16.

y= 0.003(2.04)^16 = 269.9.

Now, if we check option B y=2.04(0.003)^x, we have decay factor there 0.003.

So, it would be a decay function.

If we check y=11.27(1.00)^x we have 1.00 so it's not growing exponentially.

And 1.00(11.27)^x is growing at extremely high rate.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

step-by-step explanation: