Two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the other. if the two planes are 5472 km apart after 3 hours what is the rate of each plane

The speeds are 877 km/h and 947 km/h.

Step-by-step explanation:

The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.

They are 5472 km after 3 hours of travel.

speed = distance/time

2x + 70 = 5472/3

2x + 70 = 1824

2x = 1754

x = 877

The slower plane travels at 877 km/h.

x + 70 = 877 + 70 = 947

The faster plane travels at 947 km/h.

answer is : muchas/tipicas

have a nice day!

~recklesschicken

a

step-by-step explanation: