First answer gets branliest a truck can be rented from company a for $80 a day plus $0.50 per mile. company b charges $40 a day plus $0.60 per mile to rent the same truck. find the number of miles in a day at which the rental costs for company a and company b are the same.

There are two steps to this problem. The first step is to make an equation for the cost of each company. The cost of each one involves 2 variables. However, we can ignore the number of days since the question asks for per day.

CostA = 90 + .40(miles)

CostB = 30 + .70(miles)

We want to know when A is a better deal or when A costs less. That is when CostA < CostB. We can then substitute the right sides of our equations into the inequality. This will give:

90 + .40(miles) < 30 + .70(miles)     This is where we will now begin to solve for the number of miles.

-30                      -30                       Subtract 30 from both sides.

60 + .4(miles) < .7(miles)                Simplify

      -.4(miles)   -.4(miles)                Subtract .4(miles) from both sides

60 < .3(miles)                                 Simplify

/.3     /.3                                        Divide both sides by .3

200 < miles                                   Simplify

So for A to cost less the number of miles must be greater than 200.

nope

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a