A. on a hiking trip bob and his two friends hiked 15 miles the first day, 10 miles on the second and 7 miles on the third day. if they walked a total of 60 miles over a 5 day trip and did not walk more than 18 miles on any one day, how many miles could they have walked each of the last two days? b. if they hiked at a top speed of 6 miles per hour on flat terrain, but had to slow down when climbing hills could they have have made the trip in a single 10 hour day of sunshine? support your answer.

A. 14 miles each day.

Step-by-step explanation:

Day 1 : 15 miles

Day 2 : 10 miles

Day 3 : 7 miles

15 + 10 + 7 = 32 miles

60 - 32 = 28 miles

2 days left

28/2 = 14

14 is less than 18

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

multiply length by height. multiply the length by the height, and then double the product. work out 10 x 10 results = 100 square inches, then work out 100 x 2 = 200. the answer is 200 square inches.

step-by-step explanation: