Karen's dad's car, moving at a constant speed, covers 75 meters in 5 seconds. what is the car’s speed in km/hr? (1 km = 1000m)

10 you would take 50/ .2

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we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

you have to put the graph on here with the question

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i think the answer is a p = 78

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there are 6 sides of a hexagon, multiply 13 x 6